Barium Bromide (BaBr2) Molecular Weight Calculation

The molecular weight of Barium bromide [BaBr2] is 297.135.

Barium bromide [BaBr2] is an inorganic compound of two elements: Barium and Bromine. The molecular weight of Barium bromide is 297.135 which can be calculated by adding up the total weight (atomic weight multiplied by their number) of Barium and Bromine.

CALCULATION PROCEDURE: Barium bromide [BaBr2] Molecular Weight Calculation

Step 1: Find out the chemical formula and determine constituent atoms and their number in a Barium bromide molecule.
From the chemical formula, you will know different atoms and their number in a Barium bromide molecule. The chemical formula of Barium bromide is BaBr2. From the chemical formula, you can find that one molecule of Barium bromide has one Barium (Ba) atom and two Bromine (Br) atoms.

Step 2: Find out the atomic weights of each atom (from the periodic table).

Atomic weight of Barium (Ba): 137.327 (Ref: Pubchem-56, Ciaaw-barium)
Atomic
weight of Bromine (Br): 79.904 (Ref: Jlab-ele035)

Step 3: Calculate the molecular weight of Barium bromide by adding the total weight of all atoms.

Number of Barium atoms in Barium bromide: 1
Atomic weight of Barium: 137.327
Total weight of Barium atoms in Barium bromide: 137.327 x 1 = 137.327

Number of Bromine atoms in Barium bromide: 2
Atomic weight of Bromine: 79.904
Total weight of Bromine atoms in Barium bromide: 79.904 x 2 = 159.808

Step 4: Calculate the molecular weight of Barium bromide by adding up the total weight of all atoms.

Molecular weight of Barium bromide (BaBr2): 137.327 (Barium) + 159.808 (Bromine) = 297.135

So the molecular weight of Barium bromide is 297.135.

Barium bromide [BaBr2] Molecular Weight Calculation