# Silver Bromide (AgBr) Molecular Weight Calculation

The molecular weight of Silver bromide [AgBr] is 187.7722.

Silver bromide [AgBr] is an inorganic compound of two elements: Silver and Bromine. The molecular weight of Silver bromide is 187.7722 which can be calculated by adding up the total weight (atomic weight multiplied by their number) of Silver and Bromine.

CALCULATION PROCEDURE: Silver bromide [AgBr] Molecular Weight Calculation

Step 1: Find out the chemical formula and determine constituent atoms and their number in a Silver bromide molecule.
From the chemical formula, you will know different atoms and their number in a Silver bromide molecule. The chemical formula of Silver bromide is AgBr. From the chemical formula, you can find that one molecule of Silver bromide has one Silver (Ag) atom and one Bromine (Br) atom.

Step 2: Find out the atomic weights of each atom (from the periodic table).

Atomic weight of Silver (Ag): 107.8682 (Ref: Jlab-ele047, ciaaw-silver)
Atomic
weight of Bromine (Br): 79.904 (Ref: Jlab-ele035)

Step 3: Calculate the molecular weight of Silver bromide by adding the total weight of all atoms.

Number of Silver atoms in Silver bromide: 1
Atomic weight of Silver: 107.8682
Total weight of Silver atoms in Silver bromide: 107.8682 x 1 = 107.8682

Number of Bromine atoms in Silver bromide: 1
Atomic weight of Bromine: 79.904
Total weight of Bromine atoms in Silver bromide: 79.904 x 1 = 79.904

Step 4: Calculate the molecular weight of Silver bromide by adding up the total weight of all atoms.

Molecular weight of Silver bromide (AgBr): 107.8682 (Silver) + 79.904 (Bromine) = 187.7722

So the molecular weight of Silver bromide is 187.7722.

Silver bromide [AgBr] Molecular Weight Calculation