# Silver Telluride (Ag2Te) Molecular Weight Calculation

The molecular weight of Silver telluride [Ag2Te] is 343.3364.

Silver telluride [Ag2Te] is an inorganic compound of two elements: Silver and Tellurium. The molecular weight of Silver telluride is 343.3364 which can be calculated by adding up the total weight (atomic weight multiplied by their number) of Silver and Tellurium.

CALCULATION PROCEDURE: Silver telluride [Ag2Te] Molecular Weight Calculation

Step 1: Find out the chemical formula and determine constituent atoms and their number in a Silver telluride molecule.
From the chemical formula, you will know different atoms and their number in a Silver telluride molecule. The chemical formula of Silver telluride is Ag2Te. From the chemical formula, you can find that one molecule of Silver telluride has two Silver (Ag) atoms and one Tellurium (Te) atom.

Step 2: Find out the atomic weights of each atom (from the periodic table).

Atomic weight of Silver (Ag): 107.8682 (Ref: Jlab-ele047, ciaaw-silver)
Atomic weight of
Tellurium (Te): 127.6 (Ref: Jlab-ele052, ciaaw-tellurium)

Step 3: Calculate the molecular weight of Silver telluride by adding the total weight of all atoms.

Number of Silver atoms in Silver telluride: 2
Atomic weight of Silver: 107.8682
Total weight of Silver atoms in Silver telluride: 107.8682 x 2 = 215.7364

Number of Tellurium atoms in Silver telluride: 1
Atomic weight of Tellurium (Te): 127.6
Total weight of Tellurium atoms in Silver telluride: 127.6 x 1 = 127.6

Step 4: Calculate the molecular weight of Silver telluride by adding up the total weight of all atoms.

Molecular weight of Silver telluride [Ag2Te]: 215.7364 (Silver) + 127.6 (Tellurium) = 343.3364

So the molecular weight of Silver telluride is 343.3364.

Silver telluride [Ag2Te] Molecular Weight Calculation