The molecular weight of Barium bromide dihydrate [BaBr₂.2H2O] is 333.1658.

Barium bromide [BaBr₂] is an inorganic compound of two elements: Barium and Bromine. The dihydrate form of Barium bromide [BaBr₂.2H2O] also contains 2 water molecules. The molecular weight of Barium bromide dihydrate is 333.1658 which can be calculated by adding up the total weight (atomic weight multiplied by their number) of all its elements and water molecules.

CALCULATION PROCEDURE: Barium bromide dihydrate [BaBr₂.2H2O] Molecular Weight Calculation

Step 1: Find out the chemical formula and determine constituent atoms and their number in a Barium bromide dihydrate molecule.
From the chemical formula, you will know different atoms and their number in a Barium bromide dihydrate molecule. The chemical formula of Barium bromide dihydrate is BaBr₂.2H2O. From the chemical formula, you can find that one molecule of Barium bromide dihydrate has one Barium (Ba) atom, two Bromine (Br) atoms, and two water molecules.

Step 2: Find out the atomic weights of each atom (from the periodic table).

Atomic weight of Barium (Ba): 137.327 (Ref: Pubchem-56, Ciaaw-barium)
Atomic weight of Bromine (Br): 79.904 (Ref: Jlab-ele035)
Molecular weight of Water [H2O]: 18.0154

Step 3: Calculate the molecular weight of Barium bromide dihydrate by adding the total weight of all atoms.

Number of Barium atoms in Barium bromide dihydrate: 1
Atomic weight of Barium: 137.327
Total weight of Barium atoms in Barium bromide dihydrate: 137.327 x 1 = 137.327

Number of Bromine atoms in Barium bromide dihydrate: 2
Atomic weight of Bromine: 79.904
Total weight of Bromine atoms in Barium bromide dihydrate: 79.904 x 2 = 159.808

Number of water (H₂O) molecules in Sodium phosphate dibasic dihydrate: 2
Molecular weight of water: 18.0154
Total weight of water in Sodium phosphate dibasic dihydrate: 18.0154 x 2 = 36.0308

Step 4: Calculate the molecular weight of Barium bromide dihydrate by adding up the total weight of all atoms.

Molecular weight of Barium bromide dihydrate (BaBr₂): 137.327 (Barium) + 159.808 (Bromine) + 36.0308 (Water) = 333.1658

So the molecular weight of Barium bromide dihydrate is 333.1658.

Barium bromide dihydrate [BaBr₂.2H2O] Molecular Weight Calculation

REFERENCES:

• Pubchem-56: https://pubchem.ncbi.nlm.nih.gov/element/56
• Ciaaw-barium: https://www.ciaaw.org/barium.htm
• Jlab-ele056: https://education.jlab.org/itselemental/ele056.html
• Pubchem-Bromine: https://pubchem.ncbi.nlm.nih.gov/element/Bromine
• Jlab-ele035: https://education.jlab.org/itselemental/ele035.htm

See also:

• Hydrogen bromide dihydrate molecular weight calculation