# Barium Fluoride (BaF2) Molecular Weight Calculation

The molecular weight of Barium fluoride [BaF2] is 175.323806326.

Barium fluoride [BaF2] is an inorganic compound of two elements: Barium and Fluorine. The molecular weight of Barium fluoride is 175.323806326 which can be calculated by adding up the total weight (atomic weight multiplied by their number) of Barium and Fluorine.

CALCULATION PROCEDURE: Barium fluoride [BaF2] Molecular Weight Calculation

Step 1: Find out the chemical formula and determine constituent atoms and their number in a Barium fluoride molecule.
From the chemical formula, you will know different atoms and their number in a Barium fluoride molecule. The chemical formula of Barium fluoride is BaF2. From the chemical formula, you can find that one molecule of Barium fluoride has one Barium (Ba) atom and two Fluorine (F) atoms.

Step 2: Find out the atomic weights of each atom (from the periodic table).

Atomic weight of Barium (Ba): 137.327 (Ref: Pubchem-56, Ciaaw-barium)
Atomic
weight of fluorine (F): 18.998403163 (Ref: Pubchem-9, Ciaaw-fluorine)

Step 3: Calculate the molecular weight of Barium fluoride by adding the total weight of all atoms.

Number of Barium atoms in Barium fluoride: 1
Atomic weight of Barium: 137.327
Total weight of Barium atoms in Barium fluoride: 137.327 x 1 = 137.327

Number of Fluorine atoms in Barium fluoride: 2
Atomic weight of Fluorine: 18.99840316
Total weight of Fluorine atoms in Barium fluoride: 18.99840316 x 2 = 37.99680633

Step 4: Calculate the molecular weight of Barium fluoride by adding up the total weight of all atoms.

Molecular weight of Barium fluoride (BaF2): 137.327 (Barium) + 37.99680633 (Fluorine) = 175.323806326

So the molecular weight of Barium fluoride is 175.323806326.

Barium fluoride [BaF2] Molecular Weight Calculation