The molarity of 25% (w/w) Hydrochloric Acid is 7.68 M.
The “%” refers to solution concentration in percentage and “(w/w)” refers to solute and solution amount given in grams (i.e., percentage by weight). This means a 25% (w/w) Hydrochloric acid contains 25 g of HCl per 100 g of solution.
The density of 25% (w/w) Hydrochloric acid solution is 1.12 g/ml at 20°C which means the weight of the 1 ml of the hydrochloric acid solution is 1.12 g at 20°C.
Molarity refers to the number of moles of the solute present in 1 liter of solution. To calculate the Molarity of 25% (w/w) Hydrochloric acid (HCl), you need to know how many moles of HCl are present in 1 liter of solution. In simple words, 1 mole is equal to the molecular weight of the substance. For example, 1 mole of Hydrogen chloride is equal to 36.46 g of hydrogen chloride (Molecular Weight: 36.46). To calculate the molarity, one must first calculate how much Hydrogen chloride is present in 1 L of 25% Hydrochloric acid. Once we know the amount of HCl present in 1 L solution, we can calculate the molarity of the solution by dividing the HCl amount by the molecular weight.
Calculation procedure: Molarity of 25% (w/w) Hydrochloric acid (HCl)
|Molar mass of Hydrogen chloride||36.46 g/mole|
|Concentration of Hydrochloric acid||25% (% by mass, w/w)|
|Density of 37% Hydrochloric acid||1.12 g/ml|
Step 1: Calculate the volume of 100 grams of Hydrochloric acid.
Density = Weight/Volume
Volume = Weight/Density
The volume of 100 g of Hydrochloric acid: 100/1.12 = 89.2857 ml
Note: 25% (w/w) hydrochloric acid means 100 g of solution contains 25 g of HCl.
The volume of 100 g of Hydrochloric acid is 89.2857 ml which means 25 g of HCl is present in 89.2857 ml of Hydrochloric acid.
Step 2: Calculate how many grams of HCl is present in 1000 ml of Hydrochloric acid.
89.2857 ml of Hydrochloric acid contains = 25 grams of HCl
1 ml of Hydrochloric acid will contain = 25/89.2857 grams of HCl
1000 ml of Hydrochloric acid will contain = (1000 x 25)/89.2857 = 280.00 grams of HCl
1000 ml of Hydrochloric acid will contain 280.00 grams of HCl.
Step 3: Calculate the number of moles of HCl in 280.00 grams of HCl.
36.46 g of HCl is equal to 1 mole.
1 g of HCl will be equal to 1/36.46 moles.
280.00 grams of Hydrogen chloride will be equal to = (280.00 x 1)/36.46 = 7.68 moles
Therefore, we can say that 1 liter of Hydrochloric acid contains 7.68 moles of HCl or in other words molarity of 25% (w/w) Hydrochloric acid is equal to 7.68 M.
Molarity of 25% (w/w) Hydrochloric acid (HCl)
Calculator – Calculate the molarity of concentrated Hydrochloric acid (HCl)
Hydrogen Chloride (HCl) Molecular weight: 36.46 g/mole
Concentration of Hydrochloric acid: % (wt/wt)
(Change the % (wt/wt) concentration)
Density of glacial Hydrochloric acid: g/ml
(Change the density)
Molarity of Hydrochloric acid: 7.68 M