# Silver(I) Fluoride (AgF) Molecular Weight Calculation

The molecular weight of Silver(I) fluoride [AgF] is 126.866603163.

Silver(I) fluoride [AgF] is an inorganic compound of two elements: Silver (Ag) and Fluorine (F). The molecular weight of Silver(I) fluoride is 126.866603163 which can be calculated by adding up the total weight (atomic weight multiplied by their number) of Silver and Fluorine.

CALCULATION PROCEDURE: Silver(I) fluoride [AgF] Molecular Weight Calculation

Step 1: Find out the chemical formula and determine constituent atoms and their number in a Silver(I) fluoride molecule.
From the chemical formula, you will know different atoms and their number in a Silver(I) fluoride molecule. The chemical formula of Silver(I) fluoride is AgF. From the chemical formula, you can find that one molecule of Silver(I) fluoride has one Silver (Ag) atom and one Fluorine (F) atom.

Step 2: Find out the atomic weights of each atom (from the periodic table).

Atomic weight of Silver (Ag): 107.8682 (Ref: Jlab-ele047, ciaaw-silver)
Atomic
weight of Fluorine (F): 18.998403163 (Ref: Pubchem-9, Ciaaw-fluorine)

Step 3: Calculate the molecular weight of Silver(I) fluoride by adding the total weight of all atoms.

Number of Silver atoms in Silver(I) fluoride: 1
Atomic weight of Silver: 107.8682
Total weight of Silver atoms in Silver(I) fluoride: 107.8682 x 1 = 107.8682

Number of Fluorine atoms in Silver(I) fluoride: 1
Atomic weight of Fluorine: 18.998403163
Total weight of Fluorine atoms in Silver(I) fluoride: 18.998403163 x 1 = 18.998403163

Step 4: Calculate the molecular weight of Silver(I) fluoride by adding up the total weight of all atoms.

Molecular weight of Silver(I) fluoride (AgF): 107.8682 (Silver) + 18.998403163 (Fluorine) = 126.866603163

So the molecular weight of Silver(I) fluoride is 126.866603163.

Silver(I) fluoride [AgF] Molecular Weight Calculation