The molecular weight of Tetradecane (C14H30) is 198.3898.
Tetradecane (C14H30) is an organic compound of two elements: Carbon, and Hydrogen. The molecular weight of Tetradecane is 198.3898 which can be calculated by adding up the total weight (atomic weight multiplied by their number) of all its elements.
CALCULATION PROCEDURE: Tetradecane [C14H30] Molecular Weight Calculation
Step 1: Find the chemical formula and determine constituent atoms and their number in a Tetradecane molecule.
You will know different atoms and their number in a Tetradecane molecule from the chemical formula. The chemical formula of Tetradecane is C14H30. The chemical formula shows that one Tetradecane molecule consists of fourteen Carbon (C) atoms and thirty Hydrogen (H) atoms.
Step 2: Find out the atomic weights of each atom (from the periodic table).
Atomic weight of Carbon (C): 12.0107 (Ref: Jlab-ele006)
Atomic weight of Hydrogen (H): 1.008 (Ref: Lanl-1)
Step 3: Calculate the total weight of each atom in a Tetradecane molecule by multiplying its atomic weight by its number.
Number of Carbon atoms in Tetradecane: 14
Atomic weight of Carbon (C): 12.0107
Total weight of Carbon atoms in Tetradecane: 12.0107 x 14 = 168.1498
Number of Hydrogen atoms in Tetradecane: 30
Atomic weight of Hydrogen (H): 1.008
Total weight of Hydrogen atoms in Tetradecane: 1.008 x 30 = 30.24
Step 4: Calculate the molecular weight of Tetradecane by adding up the total weight of all atoms.
Molecular weight of Tetradecane: 168.1498 (Carbon) + 30.24 (Hydrogen) = 198.3898
So the molecular weight of Tetradecane is 198.3898.
Tetradecane [C14H30] Molecular Weight Calculation
|Molecular weight of Tetradecane [C14H30]|
|Constituent atoms||Number of each atom||Atomic weight||Total weight|
|Molecular weight of Tetradecane [C14H30]:||198.3898|
- Lanl-1: https://periodic.lanl.gov/1.shtml
- Jlab-ele006: https://education.jlab.org/itselemental/ele006.html