The molecular weight of Tetramethylethylenediamine [(CH3)2NCH2CH2N(CH3)2] is 116.20568.
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Tetramethylethylenediamine [(CH3)2NCH2CH2N(CH3)2] is an organic compound of three elements: Carbon, Hydrogen, and Nitrogen. The molecular weight of Tetramethylethylenediamine is 116.20568 which can be calculated by adding up the total weight (atomic weight multiplied by their number) of all its elements.
CALCULATION PROCEDURE: Tetramethylethylenediamine [(CH3)2NCH2CH2N(CH3)2] Molecular Weight Calculation
Step 1: Find out the chemical formula and determine constituent atoms and their number in a Tetramethylethylenediamine molecule.
From the chemical formula, you will know different atoms and their number in a Tetramethylethylenediamine molecule. The chemical formula of Tetramethylethylenediamine is (CH3)2NCH2CH2N(CH3)2. From the chemical formula, you can find that one molecule of Tetramethylethylenediamine consists of six Carbon (C) atoms, sixteen Hydrogen (H) atoms, and two Nitrogen (N) atoms.
Step 2: Find out the atomic weights of each atom (from the periodic table).
Atomic weight of Carbon (C): 12.0107 (Ref: Jlab-ele006)
Atomic weight of Hydrogen (H): 1.008 (Ref: Lanl-1)
Atomic weight of Nitrogen (N): 14.00674 (Ref: Jlab-ele007)
Step 3: Calculate the total weight of each atom in a Tetramethylethylenediamine molecule by multiplying its atomic weight by its number.
Number of Carbon atoms in Tetramethylethylenediamine: 6
Atomic weight of Carbon (C): 12.0107
Total weight of Carbon atoms in Tetramethylethylenediamine: 12.0107 x 6 = 72.0642
Number of Hydrogen atoms in Tetramethylethylenediamine: 16
Atomic weight of Hydrogen (H): 1.008
Total weight of Hydrogen atoms in Tetramethylethylenediamine: 1.008 x 16 = 16.128
Number of Nitrogen atoms in Tetramethylethylenediamine: 2
Atomic weight of Nitrogen (N): 14.00674
Total weight of Nitrogen atoms in Tetramethylethylenediamine: 14.00674 x 2 = 28.01348
Step 4: Calculate the molecular weight of Tetramethylethylenediamine by adding up the total weight of all atoms.
Molecular weight of Tetramethylethylenediamine: 72.0642 (Carbon) + 16.128 (Hydrogen) + 28.01348 (Nitrogen) = 116.20568
So the molecular weight of Tetramethylethylenediamine is 116.20568.
Tetramethylethylenediamine [(CH3)2NCH2CH2N(CH3)2] Molecular Weight Calculation
| Molecular weight of Tetramethylethylenediamine [(CH3)2NCH2CH2N(CH3)2] | |||
| Constituent atoms | Number of each atom | Atomic weight | Total weight |
| Carbon (C) | 6 | 12.0107 | 72.0642 |
| Hydrogen (H) | 16 | 1.008 | 16.128 |
| Nitrogen (N) | 2 | 14.00674 | 28.01348 |
| Molecular weight of Tetramethylethylenediamine [(CH3)2NCH2CH2N(CH3)2]: | 116.20568 | ||
REFERENCES:
- Lanl-1: https://periodic.lanl.gov/1.shtml
- Jlab-ele006: https://education.jlab.org/itselemental/ele006.html
- Jlab-ele007: https://education.jlab.org/itselemental/ele007.html
