The molecular weight of N-Nitroso-N-Methylurea (NMU) (C2H5N3O2) is 103.08042.
N-Nitroso-N-Methylurea (NMU) (C2H5N3O2) is an organic compound of four elements: Carbon, Hydrogen, Nitrogen, and Oxygen. The molecular weight of N-Nitroso-N-Methylurea (NMU) is 103.08042 which can be calculated by adding up the total weight (atomic weight multiplied by their number) of all its elements.
CALCULATION PROCEDURE: N-Nitroso-N-Methylurea (NMU) [C2H5N3O2] Molecular Weight Calculation
Step 1: Find out the chemical formula and determine constituent atoms and their number in an N-Nitroso-N-Methylurea (NMU) molecule.
You will know different atoms and their number in an N-Nitroso-N-Methylurea (NMU) molecule from the chemical formula. The chemical formula of N-Nitroso-N-Methylurea (NMU) is C2H5N3O2. From the chemical formula, you can find that one molecule of N-Nitroso-N-Methylurea (NMU) consists of two Carbon (C) atoms, five Hydrogen (H) atoms, three Nitrogen (N) atoms, and two Oxygen (O) atoms.
Step 2: Find out the atomic weights of each atom (from the periodic table).
Atomic weight of Carbon (C): 12.0107 (Ref: Jlab-ele006)
Atomic weight of Hydrogen (H): 1.008 (Ref: Lanl-1)
Atomic weight of Nitrogen (N): 14.00674 (Ref: Jlab-ele007)
Atomic weight of Oxygen (O): 15.9994 (Ref: Jlab-ele008)
Step 3: Calculate the total weight of each atom in an N-Nitroso-N-methylurea (NMU) molecule by multiplying its atomic weight by its number.
Number of Carbon atoms in N-Nitroso-N-Methylurea (NMU): 2
Atomic weight of Carbon (C): 12.0107
Total weight of Carbon atoms in N-Nitroso-N-Methylurea (NMU): 12.0107 x 2 = 24.0214
Number of Hydrogen atoms in N-Nitroso-N-Methylurea (NMU): 5
Atomic weight of Hydrogen (H): 1.008
Total weight of Hydrogen atoms in N-Nitroso-N-Methylurea (NMU): 1.008 x 5 = 5.04
Number of Nitrogen atoms in N-Nitroso-N-Methylurea (NMU): 3
Atomic weight of Nitrogen (N): 14.00674
Total weight of Nitrogen atoms in N-Nitroso-N-Methylurea (NMU): 14.00674 x 3 = 42.02022
Number of Oxygen atoms in N-Nitroso-N-Methylurea (NMU): 2
Atomic weight of Oxygen (O): 15.9994
Total weight of Oxygen atoms in N-Nitroso-N-Methylurea (NMU): 15.9994 x 2 = 31.9988
Step 4: Calculate the molecular weight of N-Nitroso-N-Methylurea (NMU) by adding up the total weight of all atoms.
Molecular weight of N-Nitroso-N-Methylurea (NMU): 24.0214 (Carbon) + 5.04 (Hydrogen) + 42.02022 (Nitrogen) + 31.9988 (Oxygen) = 103.08042
So the molecular weight of N-Nitroso-N-Methylurea (NMU) is 103.08042.
N-Nitroso-N-Methylurea (NMU) [C2H5N3O2] Molecular Weight Calculation
Molecular weight of N-Nitroso-N-Methylurea (NMU) [C2H5N3O2] | |||
Constituent atoms | Number of each atom | Atomic weight | Total weight |
Carbon (C) | 2 | 12.0107 | 24.0214 |
Hydrogen (H) | 5 | 1.008 | 5.04 |
Nitrogen (N) | 3 | 14.00674 | 42.02022 |
Oxygen (O) | 2 | 15.9994 | 31.9988 |
Molecular weight of N-Nitroso-N-Methylurea (NMU) [C2H5N3O2]: | 103.08042 |
REFERENCES:
- Lanl-1: https://periodic.lanl.gov/1.shtml
- Jlab-ele006: https://education.jlab.org/itselemental/ele006.html
- Jlab-ele007: https://education.jlab.org/itselemental/ele007.html
- Jlab-ele008: https://education.jlab.org/itselemental/ele008.html
- Pubchem-Chlorine: https://pubchem.ncbi.nlm.nih.gov/element/Chlorine